Lesson 3 of 7 · Communication delay
Plan around a reply that cannot be instant
8 minute lesson · 3 checks along the way
Your goal for this lessonCalculate one-way and round-trip light time and distinguish it from data-transfer duration.
In this lesson 4 sections · 3 checks
Using archive links & definitions
Words with a dotted underline open a short definition right here in the lesson.
Read & understand
A finite speed sets the earliest arrival
Radio waves and light travel through vacuum at about 300,000 kilometers per second. A useful rounded model is travel time equals distance divided by that speed. A probe 90 million kilometers away therefore has a one-way light time of 300 seconds, or five minutes. This example fixes the separation and ignores small propagation corrections.
Increasing transmitter power can make a message easier to receive, but cannot make it arrive before that light-time limit. A scene presented as live coverage may already depict events that happened minutes earlier. The receiving timestamp and the event timestamp answer different questions.
Check 1 of 3
10 pointsUse the reading above. You can try again without losing points.
Read & understand
A conversation has two journeys
If Earth sends a command to that fictional probe and the probe answers immediately, the earliest reply returns after another five minutes. The minimum round trip is ten minutes. Processing, scheduled contacts and time spent transmitting the message can add delays. A round-trip measurement must not be mistaken for one-way distance without the factor of two.
Real spacecraft and planets move during the exchange, so mission navigation uses more detailed models. The simple calculation is still valuable for identifying an impossible expectation. An operator cannot react to a hazard within seconds using information that takes minutes to arrive.
Read & understand
Distinguish latency from throughput
is the time before information reaches its destination. describes how much useful information arrives per unit time. A link might deliver many bits per second after a long wait for the first bit. Faster encoding or a higher rate reduces the time required to transmit a file, not the vacuum time each signal needs to cross the distance.
In another fictional example, a 60-megabit file sent at a useful rate of 2 megabits per second takes 30 seconds to transmit. With five minutes of propagation, the last bit arrives about five minutes and 30 seconds after transmission starts, assuming continuous contact and negligible other delays.
The last bit has a journey too
Original teaching diagram. Fictional useful rate · continuous link. SEND THE FILE. 60 Mb ÷ 2 Mb/s = 30 s. First bit sent at t = 0. Last bit sent at t = 30 s. CROSS THE DISTANCE. Propagation: 300 s. First arrival: 300 s. Last arrival: 330 s. Transmission duration and one-way propagation are separate contributions.
Open full-size diagram in a new tab: The last bit has a journey tooCheck 2 of 3
10 pointsUse the reading above. You can try again without losing points.
Read & understand
Move urgent decisions closer to the event
A mission can send a tested sequence in advance and allow bounded onboard responses to expected conditions. A rover might stop when a hazard check fails instead of waiting for a new command from Earth. Autonomy does not remove the human role: people choose objectives, permitted actions, limits and evidence to return.
For every proposed intervention, compare the event timescale with the complete observation-and-command loop. If the loop is too slow, redesign the response around local sensing, conservative behavior and later review. A delayed system can still be carefully supervised when its plan matches the physics.
Check 3 of 3
10 pointsUse the reading above. You can try again without losing points.
Put it together
Your lesson progress
Each check connects to a part of the story. Complete all 3 to earn your 25-point lesson bonus.
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